Вестник МГТУ. 2020, Т. 23, № 3.

Вербицкий С. Б. и др. Конструкция, расчет и применение. A series o f necessary structural, kinematic and dynamic calculations was performed, the results o f which are presented below. We determine the performance o f a vacuum meat mixer when working in a horizontal position by the formula Q = 60 x a'V x ^ = 60 x 0.4 0 15 x1100132^ , (1) T 30 h where a - the filling factor o f the capacity o f the meat mixer in the massaging mode (a = 0.4); V - the volume of the mixing tank cycle time, min. o f the mixer, V = 0.15 m3; Q - the specific gravity o f minced meat, q = 1100 kg/m3; T - the T = t 1 + t 2 + t 3 = 9 + 12 + 5 = 26 min, (2) where t 1- the duration o f loading the working bowl, min; t 2 - the duration o f the mixing process, min; t 3 - the duration o f unloading o f the working bowl, min. From the experience o f operating meat mixers o f a similar design: t 1 = 9 min, t 2 = 12 min, t 3 = 5 min. We accept for the calculation T = 30 min. Power o f the electric motor o f the drive o f the working bodies o f the vacuum meat mixer when operating in a horizontal position in terms o f specific energy consumption N - 2 ^ 2 . 2 5 * 0 132 . 0.54 kW, (3) k 0.63 where q 1 - the specific energy consumption per 1 ton o f raw meat o f minced meat consistency, q 1 = 2.5-2.6; k - the efficiency o f the geared motor k = 0.63. We determine the required torque Mo, Nm , on the output shaft o f the gear motor using the formula Mo = P 1 x L1+ P 2 x L2 + P 3 x (4) where L - the distance from the mixer axis to the point o f application o f the force (structurally L 1 = 0.254 m, L 2 = 0.132 m, L 3 = 0.143 m); Р - the resistance by this blade, N P = ct x F, (5) where F - the frontal surface o f the blade, m2 (structurally F 1 = 0.022 m2, F 2 = 0.015 m2, F 3 = 0.04 m2); ct is the corresponding resistivity, N/m2, determined by the formula ct = ct0 + a x v, (6) where o0- the specific initial resistance, N/m2 (we take o0 = 13000 N/m2); a - the constant parameter depending on the type o f raw material (we take a = 8000); v - the speed o f movement o f the corresponding blade, m/s n x n x L v = ----------- • (7) 30 When n = 12 rev/min, then M = P. x L + P 2 x L 2 +P 3 x L 3 = в 1 1 2 2 3 3 n x n x L \ r _ f nx n x L 2 . ■ 1 IL x F. + l a 0 + a ------------ IL2x F 2 + 30 I 1 1 [ 30 n x n x L 3 IL3x F3 = 30 ^1 1 3 0 0 ^ 80003' 14 x132Qx 0,254 ^x 0.254 x 0.022 + (8) 3.14 x 12 x 0.132", + | 13000 + 8000--------- —--------- Ix 0.132 x 0.015 + + | 13000 + 80003.14x12Qx 0 .143 Ix0.143x0.040 = 199 Nm. Nominal torque on the output shaft o f the selected geared motor Mn = 600 Nm. The geared motor is selected correctly because Mn >M0. Based on the data obtained and taking into account short-term overloads, we take a gear motor MV3-125- 12-330 U3, 380, electric motor power N = 0.75 kW, output shaft speed n = 12 rpm. 230